Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. This presentation will tell you what the pythagorean theorem is and how to solve questions.
Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples. This presentation will help you find the area of a right rectangular prism. This album is powered by BubbleShare - Add to my blog
Every polygon has the same number of sides as its vertices. Example: Triangle has three sides and three vertices. Square has four sides and four vertices.
This persentation will tell you about polygons and how to tell which one is which.
Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples.
Here is a power point explaining it
Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical example.
Here is a power point explaining it.
Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples. Here is a power point explaining it.
Question 4: What is a polygon and how do we classify one? A Polygon is a shape in geometry. It is a plain shape that has a line that goes all the way around the shape. The number of sides is infinite.
Types of polygons
An regular polygon is a polygon that all the lines and angles are the same length and angle.
An irregular polygon is a polygon that the lines are not all the same and the all angles are not the same.
Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. The Pythagorean Theorem is a formula discovered by Pythagoras to find out what the length of the third side of a right triangle is when the two other sides of the right triangle are given. The formula is a²+b²=c².
If the right triangle is missing a leg (hypotenuse), this is how you solve it using the formula above: 1) 35²+12²=c² 1225+144=c² 1369=c² 37in squared=c
Here is an example of a right trianle that is missing one of it's legs(a or b): 2) 72²+b²=97² 5184+b²=9409 b²=9409-5184 b²=4225 b=65cm squared
Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples. A right rectangular prism is a 3D rectangle that all of the sides have a right angle. You can find the surface area of a right rectanglar prism by using the formula:
SA=2(lenght x width)+2(length x height)+2(width x height)
This is a rectangular prism (Top) This is the net of a rectangular prism (Bottom)
To find the surface area of a rectangular prism just plug in the numbers in the formula. For example: lenght=23m width=13m height=12m Now, plug in the numbers in the formula below:
Here is a picture of a rectangular prism, let's solve for its surface area with the formula SA=2(lw)+2(lh)+2(wh):
SA=2(10*4)+2(10*5)+2(4*5)
SA=2(40)+2(50)+2(20)
SA=80+100+40
SA=220cm squared
Here is an example of a rectagular prism that we use in our everyday lives:
Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples.
A right cylinder is alot like a right rectangular prism, if you cut it open, it has right angles, and is shaped like a rectangle with two circles on it.
Here is a cylinder cut open flat (Bottom)
Here is a picture of a cylinder not cut open
To find the Surface Area of a cylinder, use the formula SA=2*pi*r squared+2*pi*r*h
pi=3.14 r=radius r squared=radius*radius h=height
For example, say if the height was 15cm, the radius was 7cm, and the diameter was 14cm, how would you solve for the surface area?
SA=2(3.14)(7)squared+2(3.14)(7)(15)
SA=6.28(49)+6.28(105)
SA=307.72+659.4
SA=967.12cm squared
Here is an example of a cylinder, a can of coke (bottom)
Here is another thing shaped like a cylinder, a tube of glue (gule stick) (top)
Question 4: What is a polygon and how do we classify one? A polygon is any shape as long as it is a closed figure. If a shape is not closed, then it is not considered a polygon. A regular polygon is a simple easy polygon that does not intersect itself anywhere. And it can be a equiangular which means that all the angles are equal. Another thing that a regular polygon can be is an equilateral which means that all the sides are the same length. Here are different types of polygons:
Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. (10 Marks)
The Pythagorean theorem is a way to determine how to calculate the lengths of all the sides on a right triangle.
To determine the Hypotenuse, one must square the Height and the Base and add together to determine the squared Hypotenuse. Then one must calculate the square-root of the squared Hypotenuse to determine the Hypotenuse.
To determine the Height, one must square the Base and the Hypotenuse. Then one must subtract the Base from the Hypotenuse, then calculate the square-root of the difference to determine the Height.
To determine the Base, one must square the Height and the Hypotenuse. Then one must subtract the Height from the Hypotenuse, then calculate the square-root the of the difference to determine the Base.
Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.(10 Marks)
The surface area of a rectangular prism is the combined total of all the sides on the prism
The formula to calculate this is: 2(lh)+2(lw)+2(hw)=sa
Say for example we have a prism with these dimensions: l=4 w=5 h=6. to determine the surface area of this we would use the formula above. 2(4x6)+2(4x5)+2(5x6)=146 The surface area is 146.
Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples. (10 Marks)
To determine the surface area of a right cylinder one must first determine the circumference of the end circles. To do this one must multiply the radius (or the diameter divided by two)by 6.28. Once this has been achieved one must then multiply the circumference by the height. Next add one of the end circles area multiplied by 2. To determine the are of the circle one must square the radius (or the diameter divided by 2) multiplied by pi. Now add this to the circumference multiplied by the height.
Question 4: What is a polygon and how do we classify one? (10 Marks
A polygon can be classified as any enclosed space। A normal polygon is a polygon where all the sides are the same length and have the same angles. These are some regular polygons. :
Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. (10 Marks)
In this slide show it will tell you all about the Pythagorean theorem. (although to view it better, you could click it again to view it in a bigger format)
Here are two videos that help explain in actions how to find a missing leg and a missing hypotenuse. If you want to look on how to solve a missing hypotenuse or leg in words it is shown in the slide show.
Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.(10 Marks)
Here again is another slide show but this time on what a right rectangular prism is and how to measure the surface area and how to find the volume.
Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples. (10 Marks)
This is a slide show all about cylinders and circles and should explain quite fairly. So enjoy.
Question 4: What is a polygon and how do we classify one? (10 Marks)
Here in this slide show it will show you all about polygons.
Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. (10 Marks)
The pythagorean theorem is the theory of Pythagoras which states the ability to calculate the objects sides'. Pythagoras stated that the hypoteneuse would be able to be calculated if the two other sides of the right triangle are available. His formula was a²+b²=c². To check if the hypoteneuse length is correct the sum of a and b should equal c. The hypoteneuse will usually be labeled c. C is the side opposite to the two other sides.
Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.(10 Marks)
A rectangular prism is a solid object where all sides are rectangles. A rectangular prism always has three dimensions. That is why it is called a three dimensional object (3-D). A rectangular prism always has six sides. It is measured with height, depth, and width. Some objects that are rectangular prisms are shoe boxes, a birthday cake, a kleenex box, etc.
Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples. (10 Marks)
A rectangular cylinder is a solid rounded figure with two circles on the top and the bottom. A rectangular cylinder is a three dimensional object (3-D). An example of a cylinder is a can, ice cream pail, an unsharpened pencil, etc.
Question 4: What is a polygon and how do we classify one? (10 Marks)
A polygon is a closed figure that is made by joining line segments together. A ploygon usually has three or more sides. All polygons have straight sides. There are two types of polygons; an irregular and regular polygon. A regular polygon is a polygon that's sides are all the same length and who's angles are all the same. An irregular polygon is a polygon that does not follow the regular polygon rules.
Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples.
The Pythagorean Theorem is the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.
Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. (10 Marks)
Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.(10 Marks)
Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples. (10 Marks)
Question 4: What is a polygon and how do we classify one? (10 Marks)
A polygon is a many sided figure, made up of closed line segments. The name of a polygon is based on how many sides it has. For example, a triangle has three sides, tri= three.
Question 1: What is the Pythagorean Theorem? The Pythagorean Theorem is a formula. The formula is used to calculate the length of a side of a right triangle (hypotenuse or either of the legs). The formula is a2 + b2 = c2.
Question 2: How do you find the surface area of a right rectangular prism?
Definition of a Right Rectangular Prism
A right rectangular prism is a 3D shape that all angles are at 90°. The rectangular prism has 6 sides called faces and 8 pairs of parallel lines.
The way to find the surface area of a rectangular prism is by using the formula below
SA= 2(lw) + 2(hw) + 2( lh) SA= 2(3x11) + 2(3x3) + 2(11x3) SA= 2(33) + 2(9) + 2(33) SA= 66 + 18 + 66 SA= 150 cm2 l= length w=width h=height Question 3: How do you find the surface area of a right cylinder? A right cylinder is a rounded rectangular prism with two circles on each base. Some everyday right cylinders are: pop cans, paper towel rolls, air tank for scuba diving, trees, totem poles, unsharpened pencils, etc.
Question 4: What is a polygon and how do we classify one?
Definition of a Polygon
A polygon is a closed figure made by joining line segments, where each line segment intersects exactly two others. A regular polygon is a polygon whose sides are all the same length, and whose angles are all the same.
Quadrilaterals are polygons with four sides. They include rectangles, squares, trapezoids, parallelograms, rhombuses. A square is a quadrilateral with four equal sides and four equal right angles. Triangles are polygons with three sides. There are several types of triangles.
Some good links for more information on what might not have been explained during the post:
Today in class we have started a new subject on measurement. On the blog there are four questions that each individual person will have to answer and put on a growing post. The growing post is consisting of only one post and to add to it it is to be edited letting you write more. This growing post will have to be finished on Friday May 4. The whole of measurement is to do with the measurement of space of a polygon (any closed shape with a face). All today that we learned in class is what exactly we have to do for this assignment and how it is to be done. We learn from lessons put up a post and answer the 4 questions that were put up on the main math blog. One last thing we learned was about the sight for our class that we can use for this project and in the main blog it is called class wiki.
Today, we had type three and four equation quiz and did some problem solving. The quiz problems are something like this :
6(x-2)=3x+2(x+1) First, you have to multiply the number outside the brackets. Next, you have to get the variable to same side. Then solve. 6x-12=3x+2x+2 6x-3x-2x=2+12 1x=14 x=14
here is another example: -3(w+2)=10+w -3w-6=10+w -3w-w=10+6 -4w=16 w=-4
We didn't learn anything new today. We worked on another review sheet. We worked on type 1, 2, 3 and 4 equations. Type 1:You have isolate the variable then solve the problem. x+7=14 x=14-7 x=7 Type 2: You have to do the addition or subtraction before you can do the multiplication or division. 2x-5=17 2x=17+5 x=22/2 x=11 Type 3:In these problems you have to get rid of the brackets, you multiply the number outside the brackets by the numbers inside the brackets. Then solve like a type 2 problem. 5(x+3)=30 5x+15=30 5x=30-15 x=15/5 x=3 Type 4: In these problems there are two variable, you have to get the variable to the same side. Then solve. 5x-7=4x+11 5x-4x=11+7 x=18
Today we learned more about type 4 equations. (The variable is on both sides) The important thing to remember is to get the variables on one side and the numbers on the other side. Here is an example of a type 4 equation. 8y-6=5y+12. Now to solve this we need to isolate the variables, so we would add them together, but once you move the variable it becomes opposite of what it used to be. Ex 5 would be -5. So now we have: 3y=6+12. Now we would just add the 6 and the 12. Now we have: 3y=18. The next step is to divide: 18/3=y. now we know that y=6. And you’re done.
The next blogger is JY
Thursday, March 22, 2007
Today we discussed how to answer a type three equation. The most important thing to know is how to use the distributive property. An example of a type three equation might be something like this:
3(x+8) = -6
The first thing you do is multiply the numbers in the brackets by the 3. Make sure they are done in order: Ex: 3 times the (x) and then 3 times the (8): Once that is done you should be left with something like this:
3x+24 = -6
Now you have a type two equation, to solve the rest of the question just complete it like a normal type 2 equation-
3x = -6-24 3x = -30 3x = -30 3 3 X = -10
If you get a question like this:
20 = 4(t/4 – 2)
First, it is often easy to switch the equation around so it looks like this:
4(t/4 – 2) = 20
Now you must add a new step. To figure out the answer do this
In today's math class we started level two algebra. Level 2 algebra is almost the same as level one algebra, but it takes two steps to get to the answer. We used the textbook page 381 to help us start level two algebra. This is a level one algebra question, x-2= 3. You would do this question in these steps. x-2= 3 x= 3+2 x= 5 This is a level two algebra question, 3x-5= 16. You would do this question in these steps. 3x-5= 16 3x= 16+5 3x= 21 x= 21/3 x= 7 Overall, level two questions are the same as level one questions with one more step. Here is a helpful link for more algebra help: http://www.math.com/school/subject2/lessons/S2U3L6GL.html
Today we did not learn anything new about algebra. We just got questions 21-48 on the second page in the worksheet. Some of those questions look like this:
X + 3/4 = 7/8 (this one is addition)
Z/16 =4 (this one division)
17X = (-3/4) (this one is multiplication)
X - 3 1/2 = (-5 2/3) (this one is subtraction) If you need some practice on type 1 or 2 algebra see this web site http://www.quia.com/rr/4096.html This is all for todays lesson. The next blogger is... MV!!!
