Jamie's Measurement Growing Post

Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples.

The Pythagorean Theorem is the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.






For example to put in in an easier way to do it:





A2+B2=C2


A: Altitude

B:base
C: Hypotneuse





Here is a Web site that might help




http://www.ies.co.jp/math/java/geo/pythagoras.html




Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.

To find the surface area of a rectangular prism you use this equation...

SA=2(lw)+2(lh)+2(hw)

L= Length
W=Width
H= Height
SA= Surface Area

How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples.

This picture below can help describe how to find the surface area...

But this is the formula that you use to find the Surface area of a right cylinder...

SA=2x3.14xR(squared)+2x3.14xRxH

H=Height

R=radius

If the radius was 3cm and the height was 10cm what would the Surface area be, get out a piece of paper and solve this equation.

these words are hard to see but try your best to read them

Question 4: What is a polygon and how do we classify one?

A Polygon is any enclosed shape. So that means that means that is could be a cube, a sphere, a prism and many other shapes.


Irregular polygons are polygons that the sides are not the same lengths and dont have the same sides.


Here are some pictures of polygons...


Here are some Irregular polygons...

Ashley's Measurement growing post

Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples.

Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.

Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples.

Question 4: What is a polygon and how do we classify one?

Michael's Measurement Growing Post

Question 1: What is the Pythagorean Theorem? You should use words, pictures, symbols and numerical examples. (10 Marks)




Question 2: How do you find the surface area of a right rectangular prism? You should use words, pictures, symbols and numerical examples.(10 Marks)



Question 3: How do you find the surface area of a right cylinder? You should use words, pictures, symbols and numerical examples. (10 Marks)




Question 4: What is a polygon and how do we classify one? (10 Marks)

A polygon is a many sided figure, made up of closed line segments. The name of a polygon is based on how many sides it has. For example, a triangle has three sides, tri= three.

These are the eight main types of Polygons:

Popel's Measurement Growing Post

Question 1: What is the Pythagorean Theorem?
The Pythagorean Theorem is a formula. The formula is used to calculate the length of a side of a right triangle (hypotenuse or either of the legs). The formula is a2 + b2 = c2.





Question 2: How do you find the surface area of a right rectangular prism?

Definition of a Right Rectangular Prism

A right rectangular prism is a 3D shape that all angles are at 90°. The rectangular prism has 6 sides called faces and 8 pairs of parallel lines.

The way to find the surface area of a rectangular prism is by using the formula below

SA= 2(lw) + 2(hw) + 2( lh)
SA= 2(3x11) + 2(3x3) + 2(11x3)
SA= 2(33) + 2(9) + 2(33)
SA= 66 + 18 + 66
SA= 150 cm2

l= length
w=width
h=height

Question 3: How do you find the surface area of a right cylinder?
A right cylinder is a rounded rectangular prism with two circles on each base. Some everyday right cylinders are: pop cans, paper towel rolls, air tank for scuba diving, trees, totem poles, unsharpened pencils, etc.


SA= 2(3.14)(r2) + 2(3.14)(h)(r)
SA= (6.28)(52) + (6.28(10)(5)
SA= 157 + 314
SA= 471cm2


Question 4: What is a polygon and how do we classify one?

Definition of a Polygon

A polygon is a closed figure made by joining line segments, where each line segment intersects exactly two others. A regular polygon is a polygon whose sides are all the same length, and whose angles are all the same.

Quadrilaterals are polygons with four sides. They include rectangles, squares, trapezoids, parallelograms, rhombuses. A square is a quadrilateral with four equal sides and four equal right angles. Triangles are polygons with three sides. There are several types of triangles.

Some good links for more information on what might not have been explained during the post:

• http://www.films.com/PreviewClip.aspx?id=216
• http://www.answers.com/topic/list-of-geometric-shapes
• 
  

Today in class we have started a new subject on measurement. On the blog there are four questions that each individual person will have to answer and put on a growing post. The growing post is consisting of only one post and to add to it it is to be edited letting you write more. This growing post will have to be finished on Friday May 4. The whole of measurement is to do with the measurement of space of a polygon (any closed shape with a face). All today that we learned in class is what exactly we have to do for this assignment and how it is to be done. We learn from lessons put up a post and answer the 4 questions that were put up on the main math blog. One last thing we learned was about the sight for our class that we can use for this project and in the main blog it is called class wiki.

http://linden8.wikispaces.com/ (this is the class wiki site here).

The next Blogger will be A.B.

Today we just reviewed doing algebra in the textbook along with problem solving.

Here are some examples on how to solve:

6(w-2)=3w+2(w+1)

6w-12=3w+2w+2

6w-3w-2w=2+12

w=14

Here is an example on how to solve a word problem:

Two times a number is equal to 20.

2x=18

x=18/2

x=9

The next blogger is N.H.!!

April 9, 2007

Today, we had type three and four equation quiz and did some problem solving.
The quiz problems are something like this :

6(x-2)=3x+2(x+1)
First, you have to multiply the number outside the brackets. Next, you have to get the
variable to same side. Then solve.
6x-12=3x+2x+2
6x-3x-2x=2+12
1x=14
x=14

here is another example:
-3(w+2)=10+w
-3w-6=10+w
-3w-w=10+6
-4w=16
w=-4

If you need more practice to solve this kind of problems see this web site:
http://www.sosmath.com/algebra/solve/solve1/s16/s16/s16.html
The next blogger is SW!

April 3, 2007

We didn't learn anything new today. We worked on another review sheet. We worked on type 1, 2, 3 and 4 equations.
Type 1: You have isolate the variable then solve the problem.
x+7=14
x=14-7
x=7
Type 2: You have to do the addition or subtraction before you can do the multiplication or division.
2x-5=17
2x=17+5
x=22/2
x=11
Type 3: In these problems you have to get rid of the brackets, you multiply the number outside the brackets by the numbers inside the brackets. Then solve like a type 2 problem.
5(x+3)=30
5x+15=30
5x=30-15
x=15/5
x=3
Type 4: In these problems there are two variable, you have to get the variable to the same side. Then solve.
5x-7=4x+11
5x-4x=11+7
x=18

If you are still having problems and the previous posts can't help try going to:
http://www.numberpower.org/BeyondBasics/Algebra/HTML/AlgebraMadeEasy.html

The next blogger is AL

Type 4 equations

Today we learned more about type 4 equations. (The variable is on both sides) The important thing to remember is to get the variables on one side and the numbers on the other side. Here is an example of a type 4 equation. 8y-6=5y+12. Now to solve this we need to isolate the variables, so we would add them together, but once you move the variable it becomes opposite of what it used to be. Ex 5 would be -5.
So now we have: 3y=6+12. Now we would just add the 6 and the 12. Now we have: 3y=18. The next step is to divide: 18/3=y. now we know that y=6. And you’re done.


The next blogger is JY

Today we discussed how to answer a type three equation. The most important thing to know is how to use the distributive property. An example of a type three equation might be something like this:

3(x+8) = -6

The first thing you do is multiply the numbers in the brackets by the 3. Make sure they are done in order:
Ex:
3 times the (x) and then 3 times the (8):
Once that is done you should be left with something like this:

3x+24 = -6

Now you have a type two equation, to solve the rest of the question just complete it like a normal type 2 equation-

3x = -6-24
3x = -30
3x = -30
3 3
X = -10

If you get a question like this:

20 = 4(t/4 – 2)

First, it is often easy to switch the equation around so it looks like this:

4(t/4 – 2) = 20

Now you must add a new step. To figure out the answer do this

4 x t = 1t
1 4

Now finnish the rest of the equation like before.

t-8 = 20
t = 20+8
t = 28

Next Blogger E.S.

6.2 solving type 2 equations

We did not learn anything new. We have been still working on Type 2 equations. Here is an example on how to do one.





Example: 3x + 2 = 14 =14-2=12
3x =12
3 divided 12 = 4
= x = 4

The next blogger is R.B

Level 2 Algebra

In today's math class we started level two algebra. Level 2 algebra is almost the same as level one algebra, but it takes two steps to get to the answer. We used the textbook page 381 to help us start level two algebra. This is a level one algebra question, x-2= 3. You would do this question in these steps. x-2= 3
x= 3+2
x= 5
This is a level two algebra question, 3x-5= 16. You would do this question in these steps.
3x-5= 16
3x= 16+5
3x= 21
x= 21/3
x= 7
Overall, level two questions are the same as level one questions with one more step.
Here is a helpful link for more algebra help: http://www.math.com/school/subject2/lessons/S2U3L6GL.html


The next blogger will be RB.

Blog post for March 15

Today we did not learn anything new about algebra. We just got questions 21-48 on the second page in the worksheet. Some of those questions look like this:

X + 3/4 = 7/8 (this one is addition)

Z/16 =4 (this one division)

17X = (-3/4) (this one is multiplication)

X - 3 1/2 = (-5 2/3) (this one is subtraction)
If you need some practice on type 1 or 2 algebra see this web site
http://www.quia.com/rr/4096.html
This is all for todays lesson. The next blogger is... MV!!!

SCRIBE POST FOR MARCH 14th

Today we didn't learn anything new. The only thing that we really learned was how to solve an equation like this:

2/5 x = 11

here are the steps:

x = (11/1)(5/2)
x = 55/2

here are some graet links:
http://www.bbc.co.uk/schools/ks3bitesize/maths/algebra/index.shtml

integers

Adding & Subtracting Integers

Mean, Median, and Mode and Probability Sites

Here is a site that you can go to for help on mean, median, and mode:
http://www.dean.tec.ma.us/MCAS/mcasmean.htm

Here is another site that can help you on probability:
http://math.youngzones.org/simple_prob.html

Study Help Bookmarks

Hi 8M - I gathered all the marks up and bookmarked each in my del.icio.us account for you to use. I will also put the link in the "Links" section to the right.

Mean, Median, Mode, Range, and Probability web sites

http://www.classbrain.com/artaskcb/publish/article_143.shtml

http://argyll.epsb.ca/jreed/math8/strand4/4201.htm

Ashley's Site Post

http://mathforum.org/library/drmath/sets/select/dm_mean_median.html mean, median, and mode

http://www.mathleague.com/help/percent/percent.htm#probability probability