8M Math (2006)

Tuesday, April 03, 2007

April 3, 2007

We didn't learn anything new today. We worked on another review sheet. We worked on type 1, 2, 3 and 4 equations.
Type 1: You have isolate the variable then solve the problem.
x+7=14
x=14-7
x=7
Type 2: You have to do the addition or subtraction before you can do the multiplication or division.
2x-5=17
2x=17+5
x=22/2
x=11
Type 3: In these problems you have to get rid of the brackets, you multiply the number outside the brackets by the numbers inside the brackets. Then solve like a type 2 problem.
5(x+3)=30
5x+15=30
5x=30-15
x=15/5
x=3
Type 4: In these problems there are two variable, you have to get the variable to the same side. Then solve.
5x-7=4x+11
5x-4x=11+7
x=18

If you are still having problems and the previous posts can't help try going to:
http://www.numberpower.org/BeyondBasics/Algebra/HTML/AlgebraMadeEasy.html

The next blogger is AL

Friday, March 23, 2007

Type 4 equations

Today we learned more about type 4 equations. (The variable is on both sides) The important thing to remember is to get the variables on one side and the numbers on the other side. Here is an example of a type 4 equation. 8y-6=5y+12. Now to solve this we need to isolate the variables, so we would add them together, but once you move the variable it becomes opposite of what it used to be. Ex 5 would be -5.
So now we have: 3y=6+12. Now we would just add the 6 and the 12. Now we have: 3y=18. The next step is to divide: 18/3=y. now we know that y=6. And you’re done.

The next blogger is JY

Thursday, March 22, 2007

Today we discussed how to answer a type three equation. The most important thing to know is how to use the distributive property. An example of a type three equation might be something like this:

3(x+8) = -6

The first thing you do is multiply the numbers in the brackets by the 3. Make sure they are done in order:
Ex:
3 times the (x) and then 3 times the (8):
Once that is done you should be left with something like this:

3x+24 = -6

Now you have a type two equation, to solve the rest of the question just complete it like a normal type 2 equation-

3x = -6-24
3x = -30
3x = -30
3 3
X = -10

If you get a question like this:

20 = 4(t/4 – 2)

First, it is often easy to switch the equation around so it looks like this:

4(t/4 – 2) = 20

Now you must add a new step. To figure out the answer do this

4 x t = 1t
1 4

Now finnish the rest of the equation like before.

t-8 = 20
t = 20+8
t = 28

Next Blogger E.S.

Tuesday, March 20, 2007

6.2 solving type 2 equations

We did not learn anything new. We have been still working on Type 2 equations. Here is an example on how to do one.

Example: 3x + 2 = 14 =14-2=12
3x =12
3 divided 12 = 4
= x = 4

The next blogger is R.B

Friday, March 16, 2007

Level 2 Algebra

In today's math class we started level two algebra. Level 2 algebra is almost the same as level one algebra, but it takes two steps to get to the answer. We used the textbook page 381 to help us start level two algebra. This is a level one algebra question, x-2= 3. You would do this question in these steps. x-2= 3
x= 3+2
x= 5
This is a level two algebra question, 3x-5= 16. You would do this question in these steps.
3x-5= 16
3x= 16+5
3x= 21
x= 21/3
x= 7
Overall, level two questions are the same as level one questions with one more step.
Here is a helpful link for more algebra help: http://www.math.com/school/subject2/lessons/S2U3L6GL.html

The next blogger will be RB.

Thursday, March 15, 2007

Blog post for March 15

Today we did not learn anything new about algebra. We just got questions 21-48 on the second page in the worksheet. Some of those questions look like this:

X + 3/4 = 7/8 (this one is addition)

Z/16 =4 (this one division)

17X = (-3/4) (this one is multiplication)

X - 3 1/2 = (-5 2/3) (this one is subtraction)
If you need some practice on type 1 or 2 algebra see this web site
http://www.quia.com/rr/4096.html
This is all for todays lesson. The next blogger is... MV!!!

Wednesday, March 14, 2007

SCRIBE POST FOR MARCH 14th

Today we didn't learn anything new. The only thing that we really learned was how to solve an equation like this:

2/5 x = 11

here are the steps:

x = (11/1)(5/2)
x = 55/2

here are some graet links:
http://www.bbc.co.uk/schools/ks3bitesize/maths/algebra/index.shtml

Thursday, February 22, 2007

integers

Adding & Subtracting Integers

Tuesday, February 06, 2007

Mean, Median, and Mode and Probability Sites

Here is a site that you can go to for help on mean, median, and mode:
http://www.dean.tec.ma.us/MCAS/mcasmean.htm

Here is another site that can help you on probability:
http://math.youngzones.org/simple_prob.html

Sunday, February 04, 2007

Study Help Bookmarks

Hi 8M - I gathered all the marks up and bookmarked each in my del.icio.us account for you to use. I will also put the link in the "Links" section to the right.